Aquadratic function has a line of symmetry at x equals -3.5 and a zero at-9 what is the distance from the given zero of the line of symmetry

12.5

Step-by-step explanation:

(9,0) (-3.5,0)

Distance formula

√(x2-x1)²+(y2-y1)²

√(9-(-3.5))²+(0-0)²

√(12.5)²

√156.25

12.5

5.5

Step-by-step explanation:

Solved it on edge. Don't wanna show the work but trust me, it's right.

sorry man i accidentally pressed yes my bad

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!