Mr. garcia pays $834 for some model cars and model planes. each model car costs $52 and each model plane costs $14 less than each model car. mr. garcia buys 3 more model planes than cars. how many model planes did he buy?

Step-by-step explanation:

Given: Total Cost = $ 834

            Price of Car = $52

            Price of Plane = $14

Let, the number of model cars be x and model planes y.

⇒ 834 = 52x + 14y (1)

Also, The number of model planes are 3 more than that of the model cars.

⇒y = x+3 (2)

Substituting the value of y from (2) in (1)

    834 = 52x + 14(x+3)

⇒  834 = 52x + 14x +42

⇒834-42 = 66x

⇒66x = 792

⇒ x=12

Substituting the value of x in (2)

y = 12+3 = 15

Therefore, Mr. Garcia bought 15 model planes.

109 is the nearest whole number/final answer! : )

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.