The graph of a polynomial function has zeros of 3 (multiplicity 2), and -7 (multiplicity 1).
write a function, in standard form, that could represent this function.

!

We want a function with three factors.  That way, the  whole thing will be zero whenever any one of the factors is zero, and we can control each factor so that it's zero when we want it to be zero.

We want one factor to be zero when x is 3, and another factor to be zero when x is 3, and another factor to be zero when x is -7.

No praaahblum !

First factor:  (x-3) .

Second factor:  (x-3) .

Third factor:  (x+7) .

See how that works ?

When we multiply these factors all together, we get the polynomial function.

(x-3) (x-3) (x+7) = x³ + x² - 33x + 63 = f(x)

That's the polynomial function you're looking for.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

33

step-by-step explanation: g=6