Solve b²-4b+4=0 using the quadratic formula explain has test on

b = 2

Step-by-step explanation by completing the square:

Solve for b over the real numbers:

b^2 - 4 b + 4 = 0

Write the left hand side as a square:

(b - 2)^2 = 0

Take the square root of both sides:

b - 2 = 0

Add 2 to both sides:

 b = 2

I'm going to use x in place of b. The reason why is because 'b' shows up in the quadratic formula, so there might be some confusion.

So we want to solve x^2 - 4x + 4 = 0 for x

Note how this equation is the same as 1x^2 - 4x + 4 = 0 and it is in the format ax^2 + bx + c = 0

We see that a = 1, b = -4 and c = 4

We will plug these values into the discriminant formula

d = b^2 - 4ac

d = (-4)^2 - 4(1)(4)

d = 16 - 16

d = 0

The discriminant is 0, so the square root of this is also 0. A discriminant of 0 means that there is only one real solution.

It turns out that the solution is equal to x = -b/(2*a) = -(-4)/(2*1) = 4/2 = 2

If the discriminant were nonzero, then the quadratic formula would be a bit messier.

It might be better to factor. Doing so gets you (x-2)^2 = 0 which becomes x-2 = 0 and x = 2

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,