What is the slope of a line that is perpendicular to the line y = 8x + 5? −8 8

The slope of the line perpendicular to the line y = 8x + 5 is

-1/8

The equation gives is a linear line which is written in the form y = bx + c

Comparing the equation given with the general form of the equation, the slope is 8

Since the line is perpendicular, the the slope is taken to be the negative reciprocal of b ;

Reciprocal of a number = 1 / number

Hence, reciprocal of 8 = 1/8

Negative 1/8 = - 1/8

Therefore, the required slope value is - 1/8

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-1/8

Step-by-step explanation:

y = 8x+5

This is in the form y= mx+b where m is the slope

The slope of the line is 8

We want a line that is perpendicular

Perpendicular lines have slopes that are negative reciprocals

m perpendicular is -1/8

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

step-by-step explanation:

classify each pair of angles as alternate interior, same-side interior, or corresponding angles.