An astronaut drops a rock into a crater on the moon. the distance, d(t), in meters, the rock travels after t seconds can be modeled by d(t)=0.8t^2. what is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?

Step-by-step explanation:

Given equation: , d(t), in meters, the rock travels after t seconds .

At t=5

The rock travels distance=

At t=10

The rock travels distance=

Total distance traveled by rock 5 and 10 seconds after it was dropped

=80-20=60 m

Total time =10-5=5 seconds

We know that the average speed =

$3720

step-by-step explanation:

taxable income = $31000

as per the 2018-2019 us tax bracket, the tax rate is 12% for an individual whose taxable income is between $9,526 to $38,700.

so, the tax to be paid by him = 12% of 31000

= 0.12 * 31000     [12% converted to decimal as 0.12]

= $3720