Abus leaves los angeles at 8am moving northeast at 60 mph. three hours later, a truck leaves the same place traveling 1 2/3 times faster than the bus on the same route. how long will it take for the truck to catch up the bus?

The truck will catch up the bus after 4.5 hours

Step-by-step explanation:

∵ The speed of the bus is 60 mph

∴ The speed of the truck = 60 × =60 × = 100 mph

∵ The bus move befor the truck by 3 hours

∴ The bus move distance = 60 × 3 = 180 miles when the truck starts to move

∴ D truck - D bus = 180

∵ D truck = 100 × t = 100t

∵ D bus = 60 × t = 60t they meet each other at the same time

∴ 100t - 60t = 180

∴ 40t = 180

∴ t = 180/40 = 4.5

∴ They meet each other after 4.5 hours

∴ The truck catch the bus after 4.5 hours from his moving

Note: you can solve it by another way that let the time of the bus is t so the time of the truck will be t - 3 and put D bus = D truck

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%