2v^2-12v-29=3

find the vertex form and vertex

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

given a quadratic in standard form : y = ax² + bx + c  : a ≠ 0

Then the x- coordinate of the vertex is

= -

Rearrange 2v² - 12v - 29 = 3 into standard form ( subtract 3 from both sides )

2v² - 12v - 32 = 0 ← in standard form

with a = 2, b = - 12, hence

= - = 3

substitute x = 3 into the equation for corresponding value of y

y = 2(3)² - 12(3) - 32 = 18 - 36 - 32 = - 50

vertex = (3, - 50)

y = 2(v- 3)² - 50 ← in vertex form

The vertex form is

The vertex is (3 , -50)

Step-by-step explanation:

∵ ⇒ , where a , b and c are constant

⇒ compare the two sides

a = 2

2ab = -12 ⇒ 2(2)b = -12 ⇒ 4b = -12 ⇒ b = -3

⇒

2 × 9 + c = -32 ⇒ c = -32 -18 = -50

∴ The vertex form is

∴ The vertex is (3 , -50)

its the fourth option