Elp ? ?
the functions f and g each represent the population of two different kinds of bacteria, where x is the time (in hours) and f and g are the number of bacteria (in thousands).

bacteria a: f(x) = 36xf(x) = 36x
bacteria b: g(x)=3xg(x)=3x

part a
between the first and fourth hour, which bacteria had a faster rate of growth? explain how you determined your answer.

Rate of growth of Bacteria A is faster than the rate of growth of Bacteria B.

Step-by-step explanation:

We are given the functions for the number of bacteria (in thousands) as,

Bacteria A :

Bacteria B : , where x represents the time (in hours).

It is required to find the faster rate of growth between 1st and 4th hour.

So, we have for Bacteria A,

Rate of growth for bacteria A =

i.e. Rate of growth for bacteria A =

i.e. Rate of growth for bacteria A =

i.e. Rate of growth for bacteria A = 559,8680

Also, we have for Bacteria B,

Rate of growth for bacteria B =

i.e. Rate of growth for bacteria B =

i.e. Rate of growth for bacteria B =

i.e. Rate of growth for bacteria B = 26

Since, Rate of growth for bacteria A = 559,8680 > 26 = Rate of growth for bacteria B.

Thus, we see that the rate of growth of Bacteria A is faster than the rate of growth of Bacteria B.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

1010: 3030

is it i think