How do you find the solution of this proportion?
4/9 = m2-1/54
m2 is m to the power of 2

±5sqrt(6)/6 = m

Step-by-step explanation:

4/9 = m^2-1/54

Add 1/54 to both sides

4/9+ 1/54 = m^2-1/54 +1/54

4/9+ 1/54 = m^2

Get a common denominator of 54

4/9 *6/6 + 1/54 = m^2

24/54 + 1/54 = m^2

25/54 = m^2

Take the square root of each side

±sqrt(25/54) = sqrt(m^2)

±sqrt(25/54) = m

±sqrt(25)/sqrt(54) = m

±sqrt(25)/sqrt(9)sqrt(6) = m

±5/3sqrt(6) = m

±5/3sqrt(6) *sqrt(6)/sqrt(6) = m

±5sqrt(6)/3*6 = m

±5sqrt(6)/6 = m

linear pair postulates