You have to find the perimeter of this shape.

J 56

Step-by-step explanation:

The area of the figure is  the large square x^2 minus the small square y^2

The area is x^2 -y^2 = 52

Since x and y are integers the of the squares must be 52

x^2 = y^2 +52

We know that it must be fairly large

Let y = 12

x^2 = 12^2 +52

x^2 = 144+52

x^2 = 196

x=14

The perimeter is the sum of the 4 sides

P = x+x + (x-y) +y+y + (x-y)

 Combining like terms

P = 4x

P = 4(14)

P = 56

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

idk lol

step-by-step explanation: