In a certain algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. there are 3 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

Using the rules of probability:

P(A∩B)=P(A)+P(B)−P(A∪B) = 22/30 + 18/30 − 27/30 = 13/30 Play both.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19