Find the area of the shaded sector. leave your answer in terms of π.

48π m2

16π m2

32π m2

64π m2

16π m2

Step-by-step explanation:

The area of a sector (A) is given by:

Where

is the angle of the sector

r is the radius of the circle

We can see that the angle of the sector is 90, and the radius of the circle is 8. Plugging these into the formula, we get:

The area is 16π m2

Option 2. 16π m².

Step-by-step explanation:

Area of a circle is represented as

Then area of an arc having angle = ∅

A' = (∅/2π)×πr²

Now we have an arc having an angle ∅ = 90° and r = 8 m

Therefore Area of the arc = (90/360)×π×8²

                                           = (1/4)×π×64

                                           = 16 π m²

So 16 π m² is the right answer.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

the correct answers i think are b. and d.

give me brainliest if it is correct!