If a+b+c=a*b*c then how many real number solutions are possible

6 solutions.

Step-by-step explanation:

1 + 2 + 3 = 6,

1*2*3 = 6.

So a = 1, b = 2 and c = 3 will fit this identity, as would any other combination of the 3 values. That is a total of 6 possible solutions. It is 6 because there are 6 possible different arrangements of 1,2 and 3.

As a matter of interest, 6 is one of  the set of 'perfect numbers' where the sum of all the factors equals their product.  The next one is 28 but that has 5 factors so that would not fit.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl