Consider the right triangle abc given below: the altitude divides triangle abc into two smaller right triangles, and all three triangles are 45-45-90 triangles

i. what is the length of the bc (x in the picture)?

ii. what is the length of cd (y in the picture)?

iii. what is the length of bd (z in the picture)?

show your work

x =8

y = 4sqrt(2)

z = 4sqrt(2)

Step-by-step explanation:

The easiest one to calculate is x

If it is a 45 -45-90 degree triangle then AB = BC=x

Since AB =8  then BC =8  and x=8

The next easiest to calculate is z

If it is a 45 -45-90 degree triangle then AD = BD=z

Using the Pythagorean theorem

z^2 +z^2 = 8^2

2z^2 =64

Divide by 2

x^2 = 32

Taking the square root of each side

z = sqrt(16)sqrt(2)

z=4sqrt(2)

Finally, we can find y

If it is a 45 -45-90 degree triangle then BD = DC

BD =z =4 sqrt(2) = DC = y

Therefore y =4 sqrt(2)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

sine

step-by-step explanation: