Brooke wants to rotate this triangle 90° clockwise about the origin. which other transformation would give exactly the same result as brooke’s rotation?

a. rotation 270° counter-clockwise about the origin

b. reflection across the y -axis

c. rotation 270° clockwise about the origin

d. reflection across the x -axis

  A.  rotation 270° counter-clockwise about the origin

Step-by-step explanation:

You can go in one direction by (some amount) around a circle to get to a specific spot, or you can go in the other direction by an amount that is (360° - (some amount)). You will get to the same spot.

  CW 90° is the same as CCW 270°

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value