Jimmy made a trip to the ferry office and back. the trip there took two hours and the trip back took three hours. he averaged 20 mph faster on the trip there than on the return trip. find jimmy's average speed on the outbound trip.

60 mph

Step-by-step explanation:

We don't know how far Jimmy drives in each direction.  Let this distance be d.  Then, d = rate * time, and d = r(2 hours)  (where r represents his speed while driving to the ferry).

But it's also true that d = (r - 20 mph)(3 hours).

Equating d = r(2 hours)  and  d = (r - 20 mph)(3 hours), we get:

r(2) = (r - 20)(3), or 2r = 3r - 60.

Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.

Jimmy averaged 60 mph on the outbound trip.

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi