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for questions 6 – 8, complete the following for the function:
(a) sketch two complete cycles of the graph.
(b) what is the period?
(c) what is the amplitude?
(d) how is this graph related to its parent graph or ?

6.) y= 5sin2x

7.) y= 3cos(x/2)

8.) y= 2sin(2πx)+1

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: and . A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or . C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl