Need this answered asap! 10 points an brainliest. only correct answers. how many triangles can be constructed with sides measuring 15 cm, 7 cm, and 5 cm?

To construct a triangle, the sum of the lengths of any two sides of the figure must be greater than the length of the remaining side.

You CANNOT construct any triangle here, because the sum of the 7 and 5 centimeter length sides (12 centimeters) is not greater than the length of the remaining side (15 centimeters).

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2