Solve the system of equations algebraically.
4x-2y=8
2x-4y=4

a. (1,1) b. no solution
c.(2,0) d. many solutions

The correct option is c.

Step-by-step explanation:

The given equations are

       ....(1)

       ....(2)

Multiply equation (1) by 2 and multiply equation (2) by 4.

       ....(3)

       ....(4)

Subtract equation (4) from equation (3).

Put this value in equation (1).

The solution of the system of equations is (2,0).

Therefore option c is correct.

Option c. (2,0)

Step-by-step explanation:

(1) 4x-2y=8

(2) 2x-4y=4

Using the method of elimination: Multiplying the second equation by -2:

(2)   -2(2x-4y)=-2(4)

Applying the distributive property:

-2(2x)-2(-4y)=-8

-4x+8y=-8

Adding this equation with the first equation:

-4x+8y+4x-2y=-8+8

6y=0

Solving for "y": Dividing both sides of the equation by 6:

6y/y=0/6

y=0

Replacing y=0 in the second equation:

(2) 2x-4(0)=4

2x-0=4

2x=4

Solving for "x": Dividing both sides of the equation by 2:

2x/2=4/2

x=2

The solution is (x,y)=(2,0)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

i think 5 miles per hour

step-by-step explanation: