What are the zeros of the function f(x)=(x+16)(2x-3)(3x+4)

see explanation

Step-by-step explanation:

given f(x) in factored form, set f(x) = 0 and solve, that is

(x + 16)(2x - 3)(3x + 4) = 0

Equate each factor to zero and solve for x

x + 16 = 0 ⇒ x = - 16

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = -

The zeroes are

x = - 16, x = , x = -

maybe showing the graph would

step-by-step explanation:

-387129 iq

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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