Aparticle moves on x-axis blah its initial position is x(0)=27 and velocity is v(t)=4t^3-30t^2+72t-54 on the time interval 0
a) write an expression for the position function (general)
t^4-10t^3+36t^2-54t+c
b) when does the particle change direction?

c) find t when particle is moving to the right

d) find velocity when acceleration is 0.
ez, don't need for this one.

b) The particle changes direction when its velocity changes sign. Use the first derivative test to find the critical points:

Then for , we have ; for , we have ; and for , we have again. These three facts indicate that the velocity only changes once at .

c) Pick "to the right" to be the positive direction. Then you need to find where . We already did that above and found for .

about 0.75 hours

step-by-step explanation:

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)