Apopulation of fish in a lake is 14000 in 2010. the population decreases 6% annually. what is the population in 2019

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: , where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

Let us find x by subtracting 2010 from 2019.

Upon substituting x=9 in our function we will get,

Therefore, the population of fish in 2019 will be 8022.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

a

step-by-step explanation: