Write the equation of the line that passes through (-2,13) and has a slope of -6

y-13 = -6(x+2) point slope form

y = -6x+1  slope intercept form

Step-by-step explanation:

We have a point and a slope which means we can use point slope form

y-y1 = m(x-x1)

y-13 = -6(x--2)

y-13 = -6(x+2)

If we want the equation in slope intercept form

Distribute the -6

y-13 = -6x-12

Add 13 to each side

y-13+13 = -6x-12+13

y = -6x+1

1,918

step-by-step explanation: