What is the length of a rectangle with an area of 48 yd^2 and a width of 3 yd?

a. 8 yd.
b 16 yd
c 18 yd
d 21 yd

=12yd

Step-by-step explanation:

The area of a rectangle is given by area=length×width

Therefore, length of a rectangle is obtained by dividing it's area with the width of the rectangle

Length=Area/Width

substituting for the values in the formula we get the following

= 48yd²/3yd

=12yd

i need more information

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?