1.state whether the relationship between the variables in the table is a direct variation, an inverse variation, or neither. if it is a direct or inverse variation, write a function to model it.

2.how do the graphs of y=1/x and y=/5x+6

compare?

Step-by-step explanation:

Left Pane

Argument

[Left Graph]: The table should be graphed to begin with. Some people don't like that idea very much, but it is a quick way to get an answer. I  took the liberty of adding 0,0

When a line goes through 0,0 the variation in this case is a direct variation. Then general equation for a direct variation is y = k*x

K is the slope. You should get 3.

m = (y2 - y1) / (x2 - x1)

Givens

Solution

Answer

Direct variation

Right Panel

Argument

The best way to show this is to (again) graph it. [Right Graph]

The last two are asymptote where if the denominator approaches these values, the hyperbola goes upwards depending on what part of the graph being observed.

The 6 has the property of moving the graph left (x + 6). And the 5 has the property of stretching the graph up and down. Note the word used is stretched not moved.

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step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b