Given 21x^3-3x^2 = 0, which values of x will satisfy the equation? (hint: factor the polynomial into two terms, and find the values of x that will make each term 0.)

B ) x = 0 and x = 2/5

Step-by-step explanation:

25 x² - 10 x = 0

5 x ( 5 x - 2 ) = 0

x = 0  and

5 x - 2 = 0

5 x = 2

x = 2: 5  

x = 2/5

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !