If a≠0, b≠0, c≠0 and a+b+c=0, then prove that a²/bc +b²/ca +c²/ab =3
the / represents a fraction

see explanation

Step-by-step explanation:

Express the left side as a single fraction with abc as the common denominator

+ +

=

[ a³ + b³ + c³ = (a + b + c)(a² + b² + c² - ab - bc - ac ) + 3abc ]

since a + b + c = 0 then

(a + b + c)(a² + b² + c² - ab - bc - ac) = 0 , hence

a³ + b³ + c³ = 3abc

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= = 3