Which values of pp and qq result in an equation with no solutions? -60x+32=qx+p−60x+32=qx+p choose all answers that apply: choose all answers that apply: (choice a) a q=-60q=−60 and p=60p=60 (choice b) b q=32q=32 and p=60p=60 (choice c) c q=-60q=−60 and p=-32p=−32 (choice d) d q=32q=32 and p=-60p=−60

  A and C

Given:

  -60x+32 = Qx+P

Find:

Which values of P and Q result in an equation with no solutions? Choose all answers that apply:

(Choice A) A Q=-60 P=60

(Choice B) B Q=32 P=60

(Choice C) C Q=-60 P=−32

(Choice D) D Q=32 P=−60

Solution:

The equation will have no solution if it reduces to ...

  0 = (non-zero constant)

If we add 60x-32 to both sides, we get

  0 = 60x +Qx + P-32

  0 = (Q+60)x +(P-32)

The x-term must be zero, so Q+60 = 0, or Q = -60.

The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.

The appropriate answer choices are those with Q=-60 and P≠32, A and C.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

need more info

step-by-step explanation: