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1. (1/2x-1)(5x^2+4x-8)

2. 4x^2-36x-32=0

show all your work and you

1.  5/2x^3 - 3x^2 - 8x + 8.

2.  9.82, -0.82  (to the nearest hundredth).

Step-by-step explanation:

1.  (1/2x  - 1)(5x^2 + 4x - 8)

= 1/2x(5x^2 + 4x - 8)  - 1 (5x^2 + 4x - 8)

= 5/2x^3 + 2x^2 - 4x - 5x^2 - 4x + 8

= 5/2x^3 - 3x^2 - 8x + 8.

2. 4x^2 - 36x - 32 = 0

   4(x^2 - 9x - 8) = 0

  x = [ -(-9) +/- √ (-9)^2 - 4 * 1 * -8) ] / 2

      = 9/ 2  +/- √(113)/2

      =  9.82, -0.82.  (answer)

x = 1; x = 8

Step-by-step explanation:

This is late but I suppose it'll come to use later for some other k12 kid.  For the second problem, you'll wanna divide everything by 4 first just to make things easier.

4x^2 / 4    -36x/4    32/4  =   0/4

This would equal to: x^4 - 9 + 8 = 0

Then, find two numbers that multiply to make 8, but add to make -9.  (If that makes sense...forgot the name of the rule.)

List the factors of 8 and see what you're working with.

1, 8

-1, -8

2, 4

-2, -4

-1 and -8 multiply to make 8 and add to make -9.  (-1 - 8 = -9); (-1 * -8 = 8)

Now we can plug this into the equation.  (x - 1)  (x - 8) = 0

So, x - 1 = 0   and   x - 8 = 0

Now simplify:  x = 1; x = 8

step-by-step explanation: