Aschool conference room can seat a maximum of 83 people. the principal and two counselors need to meet with the school’s student athletes to discuss eligibility requirements. if each student must bring a parent with them, what is the maximum number of students that can attend each meeting? a. 41 students b. 40 students c. 80 students d. 83 students

b. 40 students

Step-by-step explanation:

This scenario is so true at my school XD

But a total of 83 people. Actually 80 since the principal and two counselors are present.

Then you divide by one since it asks they must bring "a" parent. So 80 students / 1 parent = 80 students. But since parents are included you would need 40 parents at max, which corresponds to 40 students at max.

So that's your answer :D

Option (b) is correct.

Thus,  40 is the maximum number of students that can attend each meeting.

Step-by-step explanation:

 Given :  A school conference room can seat a maximum of 83 people. The principal and two counselors need to meet with the school’s student athletes to discuss eligibility requirements.

Also, given :  each student must bring a parent with them.

Total seats of school conference room is filled by principal  ,  two counselors + students and their parents.

Thus, 83 = 1 principal + 2 counselors + students + parents.

⇒  students + parents = 83 - 3

⇒  students + parents = 80

Given one student must bring one parent with them so number of students and parents must be equal. Let it be x,

⇒ x + x = 80

⇒ 2x = 80

⇒ x = 40

Thus,  40 is the maximum number of students that can attend each meeting.

Thus, option (b) is correct.

answer: get a conversion sheet out i dont know the exact measurments

step-by-step explanation: divide the number of feet with the nu,ber of milrs and there your answer