How is multiplying rational numbers like multiplying integers

Hello from MrBillDoesMath!

See Discussion below

Discussion:

Let  a/b and c/d be rational numbers we wish to multiply. Then

(a/b) * (c/d) = (a*c)/(b*d)

The numerator (a*c) is the product of two integers ( a and c) and the  denominator (b*d) is also ( b and d). In that way  multiplying rational numbers is like multiplying integers.

Thank you,

MrB

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.