What two consecutive odd integers have a sum of -28

-15 and -13

Step-by-step explanation:

Assume that x is an odd integer, if we added one to this integer it would become even and then if we added one again it would become odd again. With this said

x --> first odd integer

x + 2 --> second odd integer

We want these integers to equal -28 so:

x + (x + 2) = -28

2x + 2 = -28

2x = -30

x = -15

Then we plug in x back into (x+2) to get the second integer

-15 + 2 = -13

And to check

-15 + -13 = -28

the axial of symmetry

step-by-step explanation:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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