Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

tanΘ = -

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx =

given sinΘ = , then

cosΘ = ±  

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = -

         = - = -

tanΘ =

        = × - = -

probability for j is 1/4

while

a is 1/6

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl