Achemist has 200 ml of a 10% sucrose solution. she adds x ml of a 40% sucrose solution. the percent concentration, y, of the final mixture is given by the rational function: the chemist needs the concentration of the final mixture to be 30%. how many milliliters of the 40% solution should she add to the 10% solution to get this concentration?

We need to add 400 ml of the 40% solution

Step-by-step explanation:

We take the amount times the percent concentration and add what we mix to get the final concentration

We need the final mixture to be 30% and we have 200 +x milliliter added together so that will be the amount in the container

200 * 10 % + x* 40 % = (200+x) *30%

Change the percent to decimal form

200 * .10  + x* .40  = (200+x) *.30

Distribute the .30

20 + .4x = 60+.3x

Subtract .3x from each side

20 + .4x-.3x = 60+.3x-.3x

20 +.1x = 60

Subtract 20 from each side

20-20 +.1x = 60-20

.1x = 40

Divide by .1

.1x/.1 = 40/.1

x=400

We need to add 400 ml of the 40% solution

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

addition

step-by-step explanation: