How do you create a data set with 8 points in it that has a mean of approximately 10 and a standard deviation of approximately 1?

See below.

Step-by-step explanation:

The standard deviation  =  √  (∑(x - 10)^2 / 8 )  must be approximately = 1 if we take the mean to be 10.

This requires ∑ (x - 10)^2 to be approximately equal to 8.

The following  data set would fit the bill:

8.6  9  9  10 10  11  11  11.5.

The values of (x - 10)^2  could be 1.96, 1, 1, 0,0, 1, 1, 2.25 = 8.21

This would give a mean of about 10 and standard deviation of about 1.

the ratio of grapes to blueberries she should use is 12: 3

step-by-step explanation:

if mandie is making 15 cups of fruit salad, the ratio of grapes to blueberries she should use is 12: 3.