Aprojectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 704t. after how many seconds does the projectile take to reach its maximum height?

22 seconds

Step-by-step explanation:

h(t) = -16t2 + 704t

The maximum will occur at the axis of symmetry.

We can find the axis of symmetry at

h = -b/2a

where at^2 +bt+c

 so a = -16 and b = 704

h = -704/(2*-16)

h= -704/-32

  = 22

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

the answer is 2/54

step-by-step explanation: