Find the zeros of each function. f(x) = x^2 + 5x - 6

x=1   x=-6

Step-by-step explanation:

f(x) = x^2 + 5x - 6

What two number multiply together to give us -6 and add to give us 5

-1 *6 = -6

-1 +6 =5

(x-1) (x+6) = 0

Using the zero product property

x-1 =0   x+6 = 0

x-1+1=0+1    x+6-6=0-6

x=1   x=-6

zeros of  function f(x) = x^2 + 5x - 6 is 1 and -6

Step-by-step explanation:

Let f(x) = x^2 + 5x - 6    

To find the Zeros

consider two numbers -1 and -6

Let   -1 * 6  = 6

-1 + 6 = 5

f(x) can be written as,

f(x) = x^2 + 5x - 6

f(x) = x^2 - x + 6x - 6

f(x) = x(x - 1) + 6 (x -1 )

f(x) = (x -1 )(x + 6)

Therefore zeros of f(x) = 1 and  -6

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

idk

step-by-step explanation: