The first term of a sequence is -12. the recursive formula for the sequence is an = an-1 + 9. what are the next 3 terms in the sequence? a) -3, -15, -27 b) -3, 6, 15 c) -3, -6, -3 d) -3, -6, 3

Answer

Step-by-step explanation:

We already have the first three terms and need the next three terms.

a(n) = 9 + a(n-1).  In words:  the nth term of this sequence is 9 plus the previous term.

Thus, a(2) = 9 + a(1), or a(2) = 9 + (-1},2) = -3.

a(3) = 9 - 3 = 6

a(4) = 9 + 6 = 12

a(5) = 9 + 12 = 21

a(6) = 9 + 21 = 30

According to your definition of a(n), the next three terms are {12, 21, 30}.  Note how each new term is equal to the previous term, plus 9.

Would you please go back and ensure that you h ave copied down this problem completely and accurately.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

0.32

step-by-step explanation:

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