Taylor graphs the system below on her graphing calculator and decides that f(x)=g(x) at x=0, x=1, and x=3. provide taylor with some feedback that explains which part of her answer is incorrect and why it is incorrect. f(x)= 2x+1 g(x)= 2x^2+1

At x = 3 . It is incorrect

f(x) ! = g(x)

Step-by-step explanation:

Lets evaluate each case

x = 0

f(0) = 2*(0) +1 = 0 + 1 = 1

g(0) = 2*(0)^2 +1 = 0 + 1 = 1

Then  f(0) = g(0)  = 1

x = 1

f(1) = 2*(1) +1 = 2 + 1 = 3

g(1) = 2*(1)^2 +1 = 2 + 1 = 3

Then  f(1) = g(1)  = 3

x = 3

f(3) = 2*(3) +1 = 6 + 1 = 7

g(3) = 2*(3)^2 +1 = 18 + 1 = 19

Then  f(3) != g(3)  (They are different)

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