Select the correct answer. given: ad = cf bc = de prove: ab = ef statement reason 1. ad = cf given 2. ad = ab + bc + cd cf = cd + de + ef segment addition 3. ab + bc + cd = cd + de + ef transitive property of equality 4. ab + bc = de + ef 5. bc = de given 6. ab = ef subtraction property of equality what is the reason for the fourth statement in this proof? a. definition of collinear points b. segment addition c. subtraction property of equality d. substitution property of equality

C. Subtraction property of equality.

Step-by-step explanation:

Given AD= CF

 And BC=DE

To prove that AB=EF

Proof:

1.Statement: AD=CF

Reason: Given in question.

2. Statement: AD= AB+BC+ CD, CF= CD+DE+EF

Reason: Segment addition property because AB,BC,and CD are the segments of AB and CD,DE and DE are segments of CF.

3. Statement: AB+BC+CD=CD+DE+EF

Reason: Transitive property of equality

Transitive property: If ab=bc and bc=ca

Then   , ab=ca

4.Statement:  AB+BC= DE+EF

Reason: By using subtraction property of equality.

5. Statement:BC=DE

Reason: Given in question.

6. Statement: AB=EF

Reason: when we put BC=DE . Then we get AB+DE=DE+EF. By using subtraction property of equality .

Hence proved .

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,