Asquare and a rectangle have the same area. the length of the rectangle is 3 inches more than the side of the square. the width of the rectangle is two inches less than the side of the square. algebraically, find the side of the square. pl

  6 inches

Step-by-step explanation:

Let s represent the length of the side of the square in inches. Then the rectangle dimensions are ...

  length: s + 3

  width: s - 2

The area of the rectangle is the product of these, so is ...

  (s +3)(s -2) = s² +s -6

This is the same as the area of the square, which is s², so we have ...

  s² = s² +s -6 . . . . square area = rectangle area

  0 = s - 6 . . . . . . . subtract s²

  6 = s . . . . . . . . . . add 6

The side of the square is 6 inches.

Check

The area of the square is 6² = 36.

The area of the rectangle is 9×4 = 36. (answer meets problem conditions)

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation:

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.