Exact value of the limit as x goes to 0 of sinx^2/x

0

Step-by-step explanation:

When we plug in 0 we will get 0/0

so we apply L' Hopitals rule

We take derivative at the top and bottom

derivative of sin^2(x) is 2sin(x)* cos(x)

2sin(x)cos(x) is sin(2x)

Derivative of x  is 1

so limit becomes

Plug in 0 for x to find limit

sin(2*0) = 0

So limit value is 0

hi how are you doing today, if you need just ask me.

step-by-step explanation: