Noor brought 21 sheets of stickers. she gave him 1/3 of a sheet to each of the 45 students at recess. she wants to give teachers 1/1/2 sheets each. which inequality describes the number of teachers, t, noor could give the stickers to?

t is less than or equal to 4

15+3/2t is less than or equal to 21

Step-by-step explanation:

khan academy said i was right

Required inequality is t ≤ 4.

Step-by-step explanation:

There are 21 sheets of stickers.

Noor gave 1/3 of a sheet to each of the 45 students.

So, she gave 1 sheet to 3 students.

Therefore, the number of sheets she gave for 45 students = .

Remaining sheets = 21 - 15 = 6

Now, the number of teachers = t

Number of sheets Noor gave to one teacher =

For t teachers, the total number of sheets given = .

Clearly, this quantity should be less than or equal to the remaining sheets 6.

Hence, the required inequality is:

3t ≤ 12

t ≤ 4

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .