The slope at a point on a position versus time graph of an object is

The objects instantaneous velocity at that point

Step-by-step explanation:

On a position versus time graph, the displacement is the vertical difference between two points and the time interval is the horizontal difference.

The ratio of displacement to time interval is the the objects instantaneous velocity at that point. This ratio is also the slope of the line.

Hence, The slope at a point on a position versus time graph of an object is the objects instantaneous velocity at that point.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: