What is the surface area of a cylander round to the nearest tenth the height is 9ft and the radius is 3ft

Answer

72pi feet^2 or about 226 feet^2

Step-by-step explanation:

The shape has a side, which is now found my the circumference, multiplied by the height.

Circumference=2*pi*r

r=3 so 6pi is the circumference

Times the height is

6pi*9

54pi is the side

now add the two surfaces left, the top and bottom, which is the area of the circle, which is found with pi*r^2

pi*3^2 is 9pi, there is two of them so add 18pi to the 54pi, which is 72pi.

Pi is about 3.14 so the rounded answer is 226.

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.