If f(x) = 1 – x, which value is equivalent to |f(i)|?

Option 3

Step-by-step explanation:

We are given that

f(x) = 1-x

To find out f(i) we replace x by i

f(i) = 1-i

Thus this is a complex number with real part = 1 and imaginary part =-1

Modulus of f(i) = |1-i| =

Thus answer is option C

square root of 2

Option C is correct

 value is equivalent to |f(i)|

Step-by-step explanation:

Modulus of the complex number z = a+ib is given by:

As per the statement:

Given the function:

Substitute x = i we have;

; where, i is the imaginary part.

We have to find |f(i)|.

By definition of modulus;

⇒

⇒

Therefore, the value of |f(i)| is,

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1