The equation of a circular area rug is (x-4)^2+(y-1)^2=16. find the diameter and center of the rug a. c(-1,-4) d=4 b. c(1,4) d=8 c. c(4,1) d=4 d. c(4,1) d=8

(x-4)^2+(y-1)^2=16

The form of a circle is written as:

(x-h)^2 + (y-k)^2 = r^2

Where r is the radius h is the X-offset from the origin and k is the y offset from the origin.

In the given formula r = 4 ( 4^2 = 16)

h = 4

k = 1

The center of the circle is (h,k) = (4,1)

The answer is:

D.  C(4,1)

d=8

D. C(4,1)

d=8

Step-by-step explanation:

(x-4)^2+(y-1)^2=16

This is of the form

(x-h)^2 +(y-k)^2 = r^2

The center is (h,k) and r is the radius

(x-4)^2+(y-1)^2=4^2

The center is

(4,1) and the radius is 4

The diameter is 2 times the radius

d = 2*4 =8

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)