Iwill give you brainlest if you get it right

Note that no diagram is drawn to scale.

If the diagram in the first picture is further worked upon, we have polygon ABCDE.

Note also that line AD = 18in and line MD = 10in.
This simply means the line Am = AD - MD = 8in.

We have the height of the triangle needed to solve for the area of the triangle. Area of Triangle = 1/2×b×h
Where b is length base of the triangle and h is the length of height of the triangle.
We still need b to find the Area.

Note also that two opposite sides of parallelograms are equal. This implies that line DC = line EB which is equal to 14in.
In the third image, you can see this. Half the length of the side of the parallelogram is needed. This means 14/2 = 7in.

We can now solve for the Area of the triangle.



We have the are of the triangle to be 28in. Multiply this by 3 to find the total area of all three triangles since the three triangles are identical. Thus,
Total Area of all Triangles = 28×3 = 76in

Now, find the area of the two parallelograms.
Area of parallelogram EBCD = bh

Where b is the length of the base side and h is the height.
Hence from the diagram,

Area of parallelogram EBCD is 140in.

Total Area of both Parallelograms will be 140 ×2= 280in since both are identical.

To find the Total Area of the tile pattern add the area of the triangles and the Parallelograms. This is 76 + 280 =356in.

Your answer is 356in.