The width of a rectangle is 3 feet shorter than its length. the perimeter is 530 feet. let x equal the length of the rectangle. the formula is p = 2l + 2w. what are the length and the width of the rectangle? a. write a list of the known information and the unknown information. write an algebraic equation to show the relationship between the knowns and the unknowns. solve the equation. answer the question.

Known: perimeter = 530 feet.

Known: width = length - 3 feet

Known: it's a rectangle so

perimeter = 2×width + 2×length

Unknown: length and width

Equation:

530 feet = 2×width + 2×length

Substitute for width:

530 feet = 2×(length - 3 feet) + 2×length

If you insist on one character variable names and no units,

530 = 2(L-3) + 2L = -6 + 4L

536 = 4L

L = 134

530 feet = 2×length - 6 feet + 2×length

530 feet = 4×length - 6 feet.

(530 + 6) feet = 4×length

536 feet = 4×length

length = (536/4) feet = 134 feet

width = length - 3= 131 feet

The length of the rectangle is 134 feet.

The width of the rectangle is 131 feet.

Check: 2×134 + 2×131 = 268+262 = 530 feet

an altitude of 15,000 feet

step-by-step explanation:

d

gimmee one of those gold crowns!

~coco